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expeople1 [14]
4 years ago
10

the city gardener ordered 1680 tulip bulbs for riverside park the bulbs were shipped in 35 boxes with an equal number of bulbs i

n each box how many tulip bulbs were in each box
Mathematics
2 answers:
luda_lava [24]4 years ago
5 0

Answer: There are 48 tulip bulbs in each box .

Step-by-step explanation:

Given : The city gardener ordered 1680 tulip bulbs for riverside park .

The bulbs were shipped in 35 boxes with an equal number of bulbs in each box .

So by using DIVISION OPERATION , we have

The number of tulip bulbs in each box =1680\div35=48

Hence, there are 48 tulip bulbs in each box .

pshichka [43]4 years ago
4 0
1680/35 = 48 tulip bulbs per box
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3/4 2/3

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1.- Multiply the numerators and the denominators

3/4 x 2/3 = (3x 2) / (4 x 3)

= 6/12

2.- Simplify

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3 years ago
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<em>Which digit in 123.456 has highest value?</em>

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3 years ago
Read 2 more answers
Consider the function as representing the value of an ounce of palladium in U.S. dollars as a function of the time t in days.
viva [34]

Answer:

the average rate of change rc is 13 , 12.1 and 12.01 for h=1 , 0.1 and 0.01 respectively

Step-by-step explanation:

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the average rate of change of R(t) over the time interval [t, t + h] is

rc= [R(t+h)-R(t)] / [(t+h) -t) = [R(t+h)-R(t)] /h = 1/h * [ 30*(t+h) − 3*(t+h)²  - (  30*t − 3*t² ) ] =  (1/h) * ( 30*h - (3*t² + 6*t*h + t²) +3*t² ) = 30 - 6*t + h

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rc= 30 - 6*3 + 0.1 = 12.1

for t=3 and h=0.01

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for t=3 and h=0.001

rc= 30 - 6*3 + 0.01 = 12.001

when h goes smaller , the average rate of change gets closer to the instantaneous rate of change of R(t) in t=3 (the derivative of R in t=3) , that is

R'(t)= 30 - 6*t

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3 years ago
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3 years ago
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