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3 years ago

Draw and compare the number 62 and 69.explain which is greater than or less than.Did the tens or ones help you decide?

Mathematics

1 answer:

Len [333]3 years ago

7 0

The number 69 is greater

62<69

the tens and ones could help

[] [] [] [] [] [] 6 tens +▪▪2 ones = 62

[] [] [] [] [] [] 6 tens +▪▪▪▪▪▪▪▪▪ 9 ones = 69

You might be interested in

How to solve f/45-2/9=2/9

Serhud [2]

F/45 - 2/9 = 2/9....add 2/9 to both sides
f/45 = 2/9 + 2/9
f/45 = 4/9 ...multiply both sides by 45
f = 4/9 * 45
f = 180/9
f = 20 <===

7 0

3 years ago

Alma is estimating the proportion of students in her school district who, in the past month, read at least 1 book. From a random

Maurinko [17]

Answer:

$(0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })$

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

Step-by-step explanation:

Step:-1

Given that the random sample size 'n' = 50

The sample proportion

$p^{-} = \frac{32}{50} = 0.64$

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

$(p^{-} - Z_{0.90} \sqrt{\frac{p(1-p)}{n}, } , p^{-} +Z_{0.90} \sqrt{\frac{p(1-p)}{n} })$

Step(ii):-

Level of significance = 0.90

Z₀.₉₀ = 1.645

$(0.64 - 1.645 \sqrt{\frac{0.64(1-0.64)}{50}, } , 0.64 +1.645 \sqrt{\frac{0.64(1-0.64)}{50} })$

$(0.64 - 1.645 \sqrt{\frac{0.64(0.36)}{50}, } , 0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })$

(0.64 -1.645(0.06788) , (0.64 + 1.645(0.06788)

(0.52846 , 0.75166)

Final answer:-

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

5 0

3 years ago

PLEASE HELP

Irina-Kira [14]

2.

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

 $d = \sqrt{(3 - 1)^2 + (1 - 3)^2}$

 $d = \sqrt{(2)^2 + (2)^2}$

 $d = \sqrt{4 + 4}$

 $d = \sqrt{8}$

3.

$3y = -4x + 2$

$y = - \dfrac{4}{3} x + \dfrac{2}{3}$

Slope of line of given equation is -4/3.

Slope of perpendicular is -3/4.

3 0

4 years ago

How do you solve these?

Murrr4er [49]

Answer:

Step-by-step explanation:

The first and only rule really is to factor these down to their primes and then apply a very simple rule

For every prime, take out 1 prime for every prime under the root sign that equals the index. The rest are thrown away.

That's very wordy. Let's try and see what it means with an example

Take sqrt(27) The index is 1/2 (square root) That means we need two threes in order to apply the rule.

sqrt(27) = sqrt(3 * 3 * 3 ) For every two primes take out 1 and throw one away.

sqrt(27) = 3 sqrt(3) You can't take out that 3rd 3.

64 = 2 * 2 *2 *2 *2 * 2

4th root 64 = 2*2*2 *2 * 2 *2

for every 4th root, you get to take 1 out and throw three away.

4th root 64 = 2 fourth root (2*2)

4th root 64 = 2 fourth root (4)

- 189 = - 3 * 3 * 3 * 7

cuberoot (- 189) = For every 3 roots, you get to pull 1 out and throw the other two away.

3 cube (- 7) is your answer.

72 = 2 * 2 * 2 * 3 * 3

cube root (72) = 2 cube root(9) You don't have enough threes to do any more than what is done.

6 0

3 years ago

What is the quotient

tester [92]

Answer:

The quotient is 4x+5 and the remainder is -13

Step-by-step explanation:

Using synthetic division

-5 4 25 12

Bringing down the 4 and multiplying

-5 4 25 12

↓ -20 -25

----------------------

4 5 -13

The quotient is 4x+5 and the remainder is -13

3 0

3 years ago

Read 2 more answers