The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>required</em> answers are:
i. Distance from Chenoa's <u>house</u> to the <em>coffee shop</em> = 6.0 miles
ii. D<u>istance</u> from <em>coffee shop</em> to Chenoa's <u>school</u> = 1.5 miles
iii. <em>Distance</em> from Chenoa's <u>house</u> to her <u>school</u> = 7.5 miles
An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>alphabet</em> is referred to as the <u>unknown</u> whose <u>value</u> has to be <em>determined</em>.
In the given question, let the <u>distance</u> from the <em>coffee shop</em> to Chenoa's <u>school</u> be represented by y.
So that;
The <u>distance</u> from Chenoa's house to the <em>coffee shop</em> = (2y + 3) miles.
The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school </u>= 5y.
This implies that:
(2y + 3) + y = 5y
3y + 3 = 5y
3 = 5y - 3y
2y = 3
y = 
= 1.5
The <em>distance</em> from the <em>coffee shop</em> to Chenoa's <u>school</u> is 1.5 miles.
Thus;
(2y + 3) = ( 2(1.5) + 3)
= 6
The <u>distance</u> from Chenoa's <u>house</u> to the <em>coffee shop</em> is 6 miles.
And,
5y = 5(1.5)
= 7.5
The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school</u> is 7.5 miles.
For more clarifications on algebraic expressions, visit: brainly.com/question/12792264
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Answer:
2.04 kg
Step-by-step explanation:
Answer:
1.25.
Step-by-step explanation:
The common ratio r is 1/5 and the first term a1 = (1/5)^(1-1) = 1.
Sum to infinity = a1 / (1 - r)
= 1 / (1 - 1/5)
= 1 / 4/5
= 5/4
= 1.25 (answer)
Answer:
The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.
Step-by-step explanation:
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