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sesenic [268]
3 years ago
10

What is the algebraic way to solve -10(x-17) = -3 ? Please provide the correct solution :)

Mathematics
2 answers:
suter [353]3 years ago
5 0

Answer:173/10

Step-by-step explanation:

Rzqust [24]3 years ago
4 0

Answer:

x= 17.3

Step-by-step explanation:

-10(x-17) = -3                 equation

-10x + 170 = -3             multiply -10 to everything in parenthesis

-10x = -173                   subtract 170 from both sides of the equation

\frac{-10x}{-10}  =\frac{-173}{-10}                  divide -10 from both sides

x= 17.3

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The zeroes of f(x) = x3 + 3x2 + 2x
Bond [772]

Answer:

the answers are -2,-1,0

Step-by-step explanation:

6 0
3 years ago
If a hypothesis is not rejected at the 0.10 level of significance, it: a. may be rejected at the 0.05 level. b. must be rejected
mariarad [96]

Answer:

Option D - Will not be rejected at the 0.05 level.

Step-by-step explanation:

The significance level, which is denoted as "α", is a measure of the strength of the evidence that must be present in a sample before we can reject the null hypothesis and conclude that the effect is statistically significant. Now, this significance level must be determined before conducting an experiment.

Now, in the context of this question, the significance level is the probability of rejecting the null hypothesis when it is true. For example, a significance level of 0.05 means a 5% risk of concluding that a difference exists when there is no actual difference. Now, lower significance levels will indicate that we require stronger evidence before we can reject the null hypothesis.

Thus, if we don't reject at α = 0.1,we obviously will not reject at higher values.

Thus, looking at the options, we will not reject at 0.05 significance level.

4 0
3 years ago
Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin
Kobotan [32]

Answer:

3

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

ax^2+bx+c=0, a\neq 0

Then to resolve a quadratic equation we apply Bhaskara's formula:

x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}

x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}

It usually has two solutions.

But it could happen that \sqrt{b^2-4ac} then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0
3 years ago
What does n equal in 2(n+5)=-2
KonstantinChe [14]
1. 2n + 2*5 =2
2. 2n + 10 = 2
3. 2n = 2 -10
4. 2n= -8
5. n = -8/2
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6 0
3 years ago
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Ugo [173]
13 different combinations
4 0
3 years ago
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