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2 years ago

What is the algebraic way to solve -10(x-17) = -3 ? Please provide the correct solution :)

Mathematics

2 answers:

suter [353]2 years ago

5 0

Answer:173/10

Step-by-step explanation:

Rzqust [24]2 years ago

4 0

Answer:

x= 17.3

Step-by-step explanation:

-10(x-17) = -3 equation

-10x + 170 = -3 multiply -10 to everything in parenthesis

-10x = -173 subtract 170 from both sides of the equation

$\frac{-10x}{-10} =\frac{-173}{-10}$ divide -10 from both sides

x= 17.3

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3 years ago

16(4 1/4) distrubuted

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Step-by-step explanation:

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3 years ago

10 points!!! please help :(

daser333 [38]

To complete the identity, we need these fundamental identities:

$1)\displaystyle{sec(x)=\frac{1}{cos(x)}$

$2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)$

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Thus, by identity 1 we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}$

by identity :

$\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)$

recall the values :

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$\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0$ ,

so:

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Putting all these together, we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}$

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Answer: D

7 0

3 years ago

the sum of the angle measures triangle is 180⁰ find the measures of each angle in the triangle below

Dvinal [7]

Answer:

∠ABC= 82°

∠ACB= 82°

∠BAC= 16°

Step-by-step explanation:

∠ABC +∠ACB +∠BAC = 180° (∠ sum of △ABC)

(5x -3)° +(5x -3)° +(x -1)°= 180°

5x -3 +5x -3 +x -1= 180

11x -7= 180 (simplify)

11x= 180 +7 (+7 on both sides)

11x= 187

x= 187 ÷11

x= 17

∠ABC

= (5x -3)°

= [5(17) -3]°

= 82°

∠ACB

= ∠ABC

= 82°

∠BAC

= (17 -1)°

= 16°

Alternatively,

∠BAC

= 180° -82° -82°

= 16°

5 0

2 years ago