Given:
ABCD is a quadrilateral
AC = 12, DE = 4 and FB = 5
To find:
The area of the polygon.
Solution:
AC bisects the quadrilateral into two triangles.
Area of triangle:

<u>Area of triangle DAC:</u>



Area of triangle DAC = 24 square units.
<u>Area of triangle BAC:</u>



Area of triangle BAC = 30 square units.
Area of polygon = Area of triangle DAC + Area of triangle BAC
= 24 square units + 30 square units
= 54 square units
The area of the polygon is 54 square units.
11t=120(12)
11t=1440
t=1440/11
However t is in hours and we want to know days so:
d=(1440/11)/24
d=1440/264
d=60/11
d=5 5/11 days<span>is a mixed number 5+5/11 days. Approximately 5.45 days....</span>
Consider this set of numbers: 1, 1, 2, 2, 3, 3, 4, 7, 7, 7, 8, 9. the _____ of the set is 7.
erastova [34]
Answer:
mode
Step-by-step explanation:
The mode of the set is 7, as 7 is the number that occurs the most frequently.
Answer:
Step-by-step explanation:
its number B