Question

9.10 raised to seven is how many times as large as 3. 10 raised to negative 2

Answer 1

Answer:

49,660,733.96

Step-by-step explanation:

Required to Find

How many times is $9.1^{7}$ greater than $3.1^{-2}$

⇒

To find the required factor ,we have to divide the numbers

⇒The required number

$=\frac{9.1^{7} }{3.1^{-2} } =9.1^{7} \times3.1^{2} =5167610.19 \times 9.21=49660733.96$