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Leviafan [203]
3 years ago
6

9.10 raised to seven is how many times as large as 3. 10 raised to negative 2

Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0

Answer:

49,660,733.96

Step-by-step explanation:

Required to Find

How many times is 9.1^{7} greater than 3.1^{-2}

⇒

To find the required factor ,we have to divide the numbers

⇒The required number

=\frac{9.1^{7} }{3.1^{-2} } =9.1^{7} \times3.1^{2} =5167610.19 \times 9.21=49660733.96

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Step-by-step explanation:

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