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Aloiza [94]
3 years ago
12

Eight people were asked what the balance of their checking account at the beginning of this past week was and how much it increa

sed or decreased by the end of the week.
Create a scatter plot that represents the data that is shown in the table. The x-axis represents the beginning balance in thousands of dollars and the y-axis represents the change in the checking account in hundreds of dollars.



Name
Beginning balance

(in thousands of dollars)

Change in checking account

(in hundreds of dollars)

Billy 6 6
Barbara 4 5
Eli 3 2
Ken 1 5
Lara 8 4
Lindsey 3 8
Marie 4 2
Eduardo 5 3
Mathematics
2 answers:
TEA [102]3 years ago
6 0
Billy because she has has has beginning balance
Lapatulllka [165]3 years ago
6 0

Answer:

:D

Step-by-step explanation:

:DDDD

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2 groups of 3 tenths pls answer today I need this answer
SSSSS [86.1K]

Answer:

6/10

Step-by-step explanation:

2 groups of 3/10 =

2 × 3/10 =

6/10

3 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Which of the following best describes the type of probability used in the
irga5000 [103]

Awnser is C. Random cuz thats how i chose this answer... its was random

8 0
3 years ago
FICA deductions consist of
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Medicare
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8 0
3 years ago
Read 2 more answers
the sum of three numbers is 55. the second number is twice the first and the third number is five less than the second. What are
ArbitrLikvidat [17]

Let the first number be = x

Then the second number = 2x

The third number = 2x - 5

Their sum = 55

This can be written in an equation as =

x + 2x + 2x - 5 = 55

= x + 2x + 2x = 55 + 5 ( transposing -5 from LHS to RHS changes -5 to +5 )

= x + 2x + 2x = 60

= 5x = 60

= x = 60 ÷ 5 ( transposing ×5 from LHS to RHS changes ×5 to ÷5 )

= x = 12

The first number = x = 12

The second number = 2x = 2 × 20 = 24

The third number = 2x - 5 = 24 - 5 = 19

Therefore , the three numbers are 12 , 24 and 19 .

5 0
3 years ago
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