Answer:
Activity Rates
Consultation $150
Drawings $58
Modeling $0.7
supervision $190
Billings $1037.5
Collections $1642.5
Total overhead allocated: $ 126,826
Explanation:
First, we divide the cost of each activity over the base total to get the rate.
![\left[\begin{array}{ccccc}$Activity&Driver&cost&Total&Rate\\$Consultation&$contact hours&315000&2100&150\\$Drawings&$desing hours&104400&1800&58\\$Modeling&$square feet&32200&46000&0.7\\$supervision&$days&228000&1200&190\\$Billings&$jobs&8300&8&1037.5\\$Collections&$jobs&13140&8&1642.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D%24Activity%26Driver%26cost%26Total%26Rate%5C%5C%24Consultation%26%24contact%20hours%26315000%262100%26150%5C%5C%24Drawings%26%24desing%20hours%26104400%261800%2658%5C%5C%24Modeling%26%24square%20feet%2632200%2646000%260.7%5C%5C%24supervision%26%24days%26228000%261200%26190%5C%5C%24Billings%26%24jobs%268300%268%261037.5%5C%5C%24Collections%26%24jobs%2613140%268%261642.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now we apply this rate against the job activity measurement:
![\left[\begin{array}{ccccc}$Activity&Job&$Rate&$Allocated\\$Consultation&410&150&61500\\$Drawings&352&58&20416&\\$Modeling&7400&0.7&5180&\\$supervision&195&190&37050&\\$Billings&1&1037.5&1037.5&\\$Collections&1&1642.5&1642.5&\\$Total&&&126826&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D%24Activity%26Job%26%24Rate%26%24Allocated%5C%5C%24Consultation%26410%26150%2661500%5C%5C%24Drawings%26352%2658%2620416%26%5C%5C%24Modeling%267400%260.7%265180%26%5C%5C%24supervision%26195%26190%2637050%26%5C%5C%24Billings%261%261037.5%261037.5%26%5C%5C%24Collections%261%261642.5%261642.5%26%5C%5C%24Total%26%26%26126826%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Answer:
this is a cost minimization problem, but it is missing some numbers, so I looked for similar questions (see attached PDF):
minimization equation = 20x₁ + 22x₂ + 18x₃ (costs per ton)
where:
x₁ = mine I
x₂ = mine II
x₃ = mine III
the constraints are:
4x₁ + 6x₂ + x₃ ≥ 54 (high grade ore)
4x₁ + 4x₂ + 6x₃ ≥ 65 (low grade ore)
x₁, x₂, x₃ ≤ 7 (only 7 days per week)
using solver, the optimal solution is
2x₁, 7x₂, and 5x₃
a. The number of days Mine I should operate = <u>2 days
</u>
b. The number of days Mine Il should operate = <u>7 days
</u>
c. The number of days Mine III should operate = <u>5 days
</u>
d. The total cost of the operation for next week = <u>$284,000</u>
Answer:
What the heck is a cereal soup
Explanation:
Whatever it is it doesn't sound too apetizing.
Answer: The correct answer is b. debit to Bad Debts Expense for $1,800.
Explanation: The company adopts the aging bad debt method on receivable. The aging method is a way of classifying receivables as uncollectible based on the length of time the receivables have been outstanding and the probability of recoverability of such receivables.
To make a provision for bad debt expense: debit is passed to bad debt expense while credit is passed to allowance for doubtful accounts. The bad debt expense reports to the income statement while allowance for doubtful accounts reports to the balance sheet (statement of financial position). Based on the question, the allowance for doubtful accounts has a credit balance of $1,200; however, $3,000 was estimated to be uncollectible. In order to restate the amount to $3,000, we need to debit bad debt expense and credit allowance for doubtful accounts with $1,800 ($3,000 - $1,200).
Answer:
It will increase price for consumers, as well as cost for airlines (due to increased demand & supply)
Explanation:
Markets are at equilibrium when market demand = market supply.
If federal government imposes more safety measures on airlines & consumers. Cost for airlines rise due to increased security expenditures, so supply decreases (shifts leftwards). Customers might feel safer amidst more personal & organisational security measures, so demand increases (shifts rightwards).
Both these factors lead to increase price for consumers, as well as cost for airlines
