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Vilka [71]
3 years ago
9

How should Rhianna write the height of the Grand teton in standard form?

Mathematics
2 answers:
Gnesinka [82]3 years ago
6 0
The answer to your question is A
RSB [31]3 years ago
5 0
The answer to the question is A
You might be interested in
A gun mass of 5 kg fired a bullet of mass 10 g with the velocity of 360 km/h. What
klemol [59]

Answer:

The recoil velocity of the gun is 0.72\,\,\frac{km}{h}  and is pointing in opposite direction to the velocity of the bullet.

Step-by-step explanation:

Use conservation of linear momentum, which states that the momentum of the bullet (product of the bullet's mass times its speed) should equal in absolute value the momentum of the recoiling gun (its mass times its recoil velocity).

We also write the mass of the bullet in the same units as the mass of the gun (for example kilograms). Mass of the bullet = 0.010 kg

In mathematical terms, we have:

5\, kg * v= 0.01 \,kg\,* 360\,\frac{km}{h} \\v=\frac{0.01\,*360}{5} \,\,\frac{km}{h}\\v=0.72\,\,\frac{km}{h}

6 0
3 years ago
Please help ASAP ! Will give brainliest!
Svet_ta [14]

27) x>-6

28) x <7

29) x<= -6

30) x < 7

31) x>=-6

32) x>4

33) x > 8

34) x < 4

35 x >= 5

5 0
3 years ago
Now that his car is 5 years old, he would like to know whether the variability of gas mileage has changed. He recorded the gas m
Kamila [148]

Answer:

Now that his car is 5 years old, he would like to know whether the variability of gas mileage has changed. He recorded the gas mileage from his last eight fill-ups; these are listed here. Conduct a test at a 10% significance level to infer whether the variability has changed.

Step-by-step explanation:

6 0
3 years ago
Solve each of the following equations for x showing the algebra you used to do it. Round each answer to the nearest ten-thousand
lyudmila [28]
11)46/7 thats the answer
4 0
4 years ago
2.
Gekata [30.6K]

Answer: the system has no solution.

Step-by-step explanation:

\displaystyle\\

\left \{ {{x^2y=16\ \ \ \ \ (1)} \atop {x^2+4y+16=0\ \ \ \ \ (2)}} \right. .\\

Multiply\  both\  sides\  of\  the\  equation\ (2)\   by\  y\  (y\neq 0):\\

x^2y+4y^2+16y=0\\

We\  substitute\  equation\  (1)\  into\  equation\  (2):\\

16+4y^2+16y=0\\

4y^2+16y+16=0\\

4*(y^2+4y+4)=0\\

4*(y^2+2*y*2+2^2)=0\\

4*(y+2)^2=0\\

Divide\  both\  sides\  of\  the \ equation\  by\  4:\\

(y+2)^2=0\\

(y+2)*(y+2)=0\\

So,\ y+2=0\\

y=-2.\\

\displaystyle\\We\  substitute\  the\  value\  of\  y\  into\  equation\  (1):\\x^2*(-2)=16\\Divide\  both\  sides\  of\  the \ equation\  by\  -2:\\x^2=-8\\x^2\geq 0\\ Hence,\ the\ system\ has\ no\ solution.

7 0
2 years ago
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