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Inessa [10]
3 years ago
8

Hich quadrilateral names apply to the figure?

Mathematics
1 answer:
marta [7]3 years ago
5 0
I think it applies to all the shapes

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What is the volume of the space filled with tissue paper in the packaging box? 81.84 cubic centimeters 105.84 cubic centimeters
Svetllana [295]

The volume of the space filled with tissue paper in the packaging box is 198.264 cubic centimeters

Let l,b,h be the dimensions of small gift box V1 = Volume = l*b*h

= 24cm^3

Dimension of Large box are 2.1l , 2.1b,2.1h

Volume of large box = 2.1 l*2.1b*2.1h

= (2.1)^3*lbh

= (2.1)^3*24

V2 =222.264

Volume filled with tissue paper is V2-V1

222.264 - 24

= 198.264cm^3

Hence The volume of the space filled with tissue paper in the packaging box is 198.264 cubic centimeters

The complete question is shown below

Zoe is packaging a gift to send in the mail. A smaller gift box is placed inside a similar yet larger packaging box. The empty space inside the packaging box is filled with tissue paper to keep the gift box from moving. The dimensions of the larger box are each 2.1 times longer than the corresponding dimensions of the smaller box. The volume of the smaller box is 24 cubic centimeters.What is the volume of the tissue paper in the packaging box?

Learn more about the volume here

brainly.com/question/1972490

#SPJ1

6 0
2 years ago
(03.06 MC)The volume of two spheres is shown: Sphere A = 40 cubic inches Sphere B = 10 cubic inches How many inches more is the
dem82 [27]

0.8 inches

the volume (V) of a sphere is calculated using the formula

V = \frac{4}{3}πr³

change the subject and express in terms of r

multiply both sides by 3

3V = 4πr³ ( divide both sides by 4π )

r³ = 3V / 4π ( take the cube root of both sides )

r = ∛( 3V /4π )

sphere A with V= 40

r = ∛ (120 / 12.56 ) = 2.122

sphere B with V = 10

r = ∛(30 / 12.56 ) = 1.337

sphere A - sphere B = 2.122 - 1.337 = 0.8 inches ( to nearest tenth )



6 0
3 years ago
Read 2 more answers
The graph below describes the journey of a train between two cities
nataly862011 [7]

Answer:

Step-by-step explanation:

To find : Acceleration in first 15 min . Distance between two cities  Average speed of journey

Solution:

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                    Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Distance between two cities

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

Average Speed of journey = 125/2  = 62.5  km/hr

Acceleration in first 15 min = 200  km/h²

Distance between two cities = 125 km

Average Speed of journey =  62.5  km/hr

Hope this helps..

8 0
3 years ago
Read 2 more answers
You buy a movie for 19.99 and a set of earphones for 12.49 how much is the bill before taxes
-BARSIC- [3]
19.99+12.49=32.48
19.99 for the movie and 12.49 for the earphones together they make 32.48
7 0
3 years ago
Read 2 more answers
The boiling point of water is 212°F. The boiling point of helium is –452°F. How would you compare the temperatures using an ineq
KatRina [158]
-452°F < 212°F
A negative number is always less than a positive.
6 0
3 years ago
Read 2 more answers
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