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mario62 [17]
3 years ago
13

Need help with the composition of functions. I have attached a screenshot of the question.

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

(f∘f)(x) = x⁴ -12x² +30

(g∘g)(x) = x/9

Step-by-step explanation:

a) (f∘f)(x) = f(f(x)) = f(x² -6)

... = (x² -6)² -6

... = x⁴ -12x² +36 -6

... (f∘f)(x) = x⁴ -12x² +30

b) (g∘g)(x) = g(g(x)) = g(x/3)

... = (x/3)/3

... (g∘g)(x) = x/9

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Solve the equation 91 = 43 + x. Explain your answer.
lana66690 [7]

Answer:

Step-by-step explanation:

The first question:

91 = 43 + x

x = 91 - 43

x = 48

By using transposing method

Second question:

7 0
4 years ago
I need help please :(
zloy xaker [14]

Answer:

-(1/3 · 1/3 · 1/3 · 1/3 )

Step-by-step explanation:

-(3)^-4= -1/3 ^4 = -1/81

-(1/3 · 1/3 · 1/3 · 1/3 )= -1/81

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3 years ago
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ASAP PLEASE HELP ME :(((
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Answer:

59/500 * x/75000

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3 years ago
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Please Help!
jeka94

Answer:

A

Step-by-step explanation:

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5 0
2 years ago
What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)?
olga2289 [7]

Step 1

<u>Find the slope of the given line</u>

Let

A(-3,2)\ B(2,-1)

slope mAB is equal to

mAB=\frac{(y2-y1)}{(x2-x1)} \\ \\ mAB=\frac{(-1-2)}{(2+3)} \\ \\ mAB=-\frac{3}{5}

Step 2

<u>Find the slope of the line that is perpendicular to the given line</u>

Let

CD ------> the line that is perpendicular to the given line

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}

Step 3

<u>Find the equation of the line with mCD and the point (3,0)</u>

we know that

the equation of the line in the form point-slope is equal to

y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5

Multiply by 3 both sides

3y=5x-15

5x-3y=15

therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation 5x-3y=15

4 0
3 years ago
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