Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
The answer —-14 I think hope I’m right
The acceleration is 5/6
(Im not that sure bout it tho)
Answer:
5=b
Step-by-step explanation:
Eliminate the parenthiesies --> n-2+7 = bn
Move the variables to one side (they cancel eachother out) --> -2+7 = bn
Solve --> 5=b
The equation of line that passes through the point(5,-3) and is parallel to the line 4x-5y=45 is:
Step-by-step explanation:
Given equation is:
First of all we have to convert the equation in slope-intercept form
So,
Let m1 be the slope of given line and m2 be the slope of required line
The coefficient of x is the slope of the line, so
m1 = 4/5
As the required line is parallel to given line, both will have equal slopes
m2 = 4/5
Slope-intercept form is:
Putting the value of m2
Putting the point (5,-3) in the equation
Putting the value of b
Hence,
The equation of line that passes through the point(5,-3) and is parallel to the line 4x-5y=45 is:
Keywords: Slope, equation of line
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