<u>Answer-</u>
<u>Solution-</u>
The dimensions of the cuboid is, 80×80×140 cm
So, its volume will be cm³
The dimensions of the cylinder is, radius = 40cm, height = 70cm
So, its volume will be cm³
Total volume,
As we know,
Answer:
Quotient: x+7
Remainder: -2
Step-by-step explanation:
Divide the terms (x² ÷ x =x)↓
(x² + 11x + 26) ÷ (x + 4) =x
Subtract x² + 4x (You have to the sign if each term)
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
Divide the terms (7x ÷ x = 7)
x² + 11x + 26) ÷ (x + 4) =x + 7
Multiply the quotient by the dividend (x + 4) × 7 = 7x+28
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
7x + 28
------------------
= -2 Remainder
Answer:
<h3>There are no solutions.</h3>
Step-by-step explanation:
<u>Questions:</u>
- Solve: 5.6= 3.1 – 12.5|1 – 0.8x|
<u>To find:</u>
<u>Solutions:</u><u>
</u>
- 5.6= 3.1 – 12.5|1 – 0.8x|
First, do switch sides.
<u>Multiply by 10 from both sides.</u>
<u>Solve.</u>
31-125|1-0.8x|=56
<u>Subtract by 31 from both sides.</u>
<u>Solve.</u>
<u>Divide by -125 from both sides.</u>
<u>Solve.</u>
- <u>Therefore, the correct answer is "D. There are no solutions."</u>
<u></u>
I hope this helps, let me know if you have any questions.
Answer:
$75
Step-by-step explanation:
Answer:
$28.83
Step-by-step explanation:
We will use: and then use cross multiplication.
Let's solve the first sale
We have:
percent = 25%
whole = $200
we want to solve for "part". Lets set the equation up before we plug anything in
now plug everything in:
part = $50
what does this mean?
Well it actually means $50 is the amount of money we take away from our original price of $200.
So we subtract that from our total.
$200 - $50 = $150
Next we will do the second sale.
percent = 50%
whole = $150
Use the same equation as above:
part = $75
Answer:
a. Expected frequency of losses per semester = 0*0.08 + 5*0.16 + 10*0.28 + 15*0.32 + 20*0.14 + 25*0.02
Expected frequency of losses per semester = 11.7 losses per semester
b. Variance = (0-11.7)²*0.08 + (5-11.7)²*016 + (10-11.7)²*0.28 + (15-11.7)²*0.32 + (20-11.7)²*0.14 + (15-11.7)²*0.02
Variance = 10.9512 + 7.1824 + 0.8092 + 3.7848 + 9.6446 + 3.5378
Variance = 35.61
c. As losses equal $60, expected losses per semester = 11.7*$60 = $702
d. Expected losses of all textbooks per semester = 250*11.7*$60 = $175,500