All categories

3 years ago

What is the solution of the inequality -6x-17≥8x+25

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

6 0

X≤-7/4 ...... thats the solution

Aleksandr-060686 [28]3 years ago

3 0

-6x -17> 8x + 25.
Get x on one side; Subtract 8x from both sides.
-14x -17 > 25.
Add 17 to both sides to get x by itself.
-14x>42.
Divide both sides by -14 (remember to flip the inequality when dividing by negatives).
x <_ 3 is your solution (line under the inequality).
I hope this helps!

You might be interested in

In a discus competition an athlete threw the discus 63.37 meters 62.92 meters and 63.7 meters order the distances from least to

maksim [4K]

62.92 meters, 63.37 meters, 63.7 meters

4 0

3 years ago

Identify the number of solutions. Y< -1/3x+5, y> -1/3x-1.

Elenna [48]

Answer: C. No solution. ( top shaded. Middle not. Bottom shaded.

Step-by-step explanation:

Given inequalities

y< -1/3x+5 and

y> -1/3x-1.

If we draw graph for y< -1/3x+5 equation, it would be a dotted line and we would shade down the dotted line because we have less than < symbol there.

Now, if we draw graph for second inequality y> -1/3x-1, it would also be a dotted line and we would shade up of dotted line because we have greater than > symbol there.

Now, we can see that slopes of both dotted lines are same that is -1/3.

So, there would not be any common shaded region.

Therefore, there would not by any solution of the system of inequalities.

And correct option is C option.

C. No solution. ( top shaded. Middle not. Bottom shaded.

8 0

3 years ago

Andrew took a math test with 40 questions. If he scored an 85%, how many questions did he get correct?

puteri [66]

Andrew answered 34 questions correctly.
I got the answer by divided the 85% by 100% (100% because it's the total percentage.) I received 0.85 when dividing that. Then, I took the 0.85 and divided it by the total of 40 questions, and that gave me the answer of 34.

4 0

3 years ago

Solve for B in the proportion below

iogann1982 [59]

Answer:

b=15

Step-by-step explanation:

7(b+1)=2*56 (we cross multiply)

7b+7=112

7b=105

b=15

7 0

2 years ago

Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.

irina1246 [14]

Lagrange multipliers:

$L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)$

$L_x=y^2z^2+\lambda=0$
$L_y=2xyz^2+\lambda=0$
$L_z=2xy^2z+\lambda=0$
$L_\lambda=x+y+z-5=0$

$\lambda=-y^2z^2=-2xyz^2=-2xy^2z$

$-y^2z^2=-2xyz^2\implies y=2x$ (if $y,z\neq0$ )

$-y^2z^2=-2xy^2z\implies z=2x$ (if $y,z\neq0$ )

$-2xyz^2=-2xy^2z\implies z=y$ (if $x,y,z\neq0$ )

In the first octant, we assume $x,y,z>0$ , so we can ignore the caveats above. Now,

$x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2$

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of $f(1,2,2)=16$ .

We also need to check the boundary of the region, i.e. the intersection of $x+y+z=5$ with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force $f(x,y,z)=0$ , so the point we found is the only extremum.

4 0

3 years ago