Answer:
The 90% confidence interval for the mean µ of the population of female runners.
( 65.0328 , 66.5672)
Step-by-step explanation:
<u>Step(i)</u>
Given A sample of 12 runners showed a sample mean height of 65.80 inches and a sample standard deviation of 1.95 inches.
Given sample size is n = 12 <30 so small sample
Given sample mean (x⁻) = 65.80 inches
sample standard deviation (S) = 1.95 inches.
<u>Step(ii)</u>
Assume the population is approximately normal.
The 90% confidence interval for the mean µ of the population of female runners.
substitute all above interval
The degrees of freedom γ=n-1 = 12-1=11
From t- table = 1.363 at 90 % 0r 0.10 level of significance
on calculation , we get
(65.80 -0.7672 ,65.80 + 0.7672)
( 65.0328 , 66.5672)
23 7/12 + 19 5/6
23 7/12 + 19 10/12
42 17/12 or 43 5/12
The answer is B. And I am not that sure about my answer, but it has to be the correct answer for what you put. THANK YOU!!!!
Answer:
Let's define:
C = number of pandesal with cheese that you sell
U = number of pandesal with ube that you sell.
If you sell these numbers of each, the total profit you get is:
C*8.00 pesos + U*9.00 pesos.
And yo want to get at least 180 pesos, then:
C*8.00 pesos + U*9.00 pesos ≥ 180 pesos.
And you also want to sell two of each, then:
C ≥ 2
U ≥2
So the system of inequalities is:
C*8.00 pesos + U*9.00 pesos ≥ 180 pesos.
C ≥ 2
U ≥2
If U is on the x-axis, and C is on the y-axis, then the graph is: (where the region at the right of the vertical line should be shaded)
Answer:
I think it is ± 2y−2X1 −22y− 2X1−2+4=x2=x
Step-by-step explanation:
hope this helps if not let me know
