well, the triangle is an isosceles, so it twin sides, and the twin sides make twin angles, as we see by the tickmarks on A and C, meaning AB = BC.
![\bf x+4=3x-8\implies 4=2x-8\implies 12=2x\implies \cfrac{12}{2}=x\implies 6=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ AC\implies x+4\implies 6+4\implies 10](https://tex.z-dn.net/?f=%5Cbf%20x%2B4%3D3x-8%5Cimplies%204%3D2x-8%5Cimplies%2012%3D2x%5Cimplies%20%5Ccfrac%7B12%7D%7B2%7D%3Dx%5Cimplies%206%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20AC%5Cimplies%20x%2B4%5Cimplies%206%2B4%5Cimplies%2010)
Answer:
10 go into 450 45 times
Step-by-step explanation:
Answer:
Real
Step-by-step explanation:
i^6-122-7i^2
(i^2)^3-122-7i^2
(-1)^3-122-7×(-1)
-1-122+7
-123+7
-116
So the final answer is -116
Answer:
2nd debate was 3 hours long.
Step-by-step explanation:
We have been given that during the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours. The second one was 1 4/5 times as long as the first one.
Let us find the estimate of time spent on 2nd debate.
1 2/3 hours would be approximately 2 hours. 1 4/5 times would be equal to 2 times.

Therefore, the estimated time is less 4 hours.
To find the time spent on 2nd debate, we will multiply 1 2/3 by 1 4/5.
First of all, we will convert mixed fractions into improper fractions as:


Now, we will multiply both fractions as:



Therefore, the 2nd debate was 3 hours long.
Answer:
Step-by-step explanation: