Answer:
3 times
Explanation:
When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model

Where:
Initial thickness,
= 2mm
Growth factor, r =8%=0.08
We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.
i.e When 

Therefore, the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm thick is 3.
Answer: uhh what?? im confused
The circuit that are in parallel circuits are option A and option B.
<h3>What are parallel circuits?</h3>
A parallel circuit has branches that divide the current so that just a portion of it passes through each branch.
A parallel circuit has the same voltage (or potential difference) across each branch, but the currents might vary.
Thus, the correct options are A and option B.
Learn more about parallel circuits
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