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Virty [35]
4 years ago
9

Please in desperate Evaluate C(20, 18).

Mathematics
1 answer:
laila [671]4 years ago
6 0
\bf _nC_r=\cfrac{n!}{r!(n-r)!}\qquad 
\begin{cases}
n=20\\
r=18
\end{cases}\implies _{20}C_{18}=\cfrac{20!}{18!(20-18)!}
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Answer:

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Step-by-step explanation:

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