Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q = -
= 0
Sum of angles in a triangle =
<P + <Q + <S =
048° + 0 + <S =
+ <S =
<S = -
=
<S =
Applying the Sine rule,
= =
=
=
=
⇒ y =
= 12.703
y = 12.70 km
=
=
=
⇒ x =
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Answer:
x = - 1
Step-by-step explanation:
Given
- 2(bx - 5) = 16 ← substitute b = 3
- 2(3x - 5) = 16 ( divide both sides by - 2 )
3x - 5 = - 8 ( add 5 to both sides )
3x = - 3 ( divide both sides by 3 )
x = - 1
Turn it into slope-intercept form.
2y = -x + 14
y = -x/2 + 7
The slope is -1/2.
Perpendicular lines have slopes that are opposite reciprocal, so the slope of the perpendicular line is 2.