Answer:
12 quarters 23 dimes
Step-by-step explanation:
x(0.25)+(2x-1)(0.10)=5.30
0.25x+0.2x-0.10=5.30
0.45x=5.40
x=12
12 quarters
12(2)=24-1=23 dimes
Answer:
the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.
Step-by-step explanation:
The variation of the concentration of salt can be expressed as:

being
C1: the concentration of salt in the inflow
Qi: the flow entering the tank
C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)
Qo: the flow going out of the tank.
With no salt in the inflow (C1=0), the equation can be reduced to

Rearranging the equation, it becomes

Integrating both sides

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

The final equation for the concentration of salt at any given time is

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

Answer:
no
Step-by-step explanation:
Direct variation is of the form
y = kx
This has a constant added
y = kx+b so it is not a direct variation
You have to match up the sides. So you have two x values of 7, and one of -3, so that suggest that the x value you're looking for is -3. You have two y-values of 1, and one of -4, so i'd say look for a negative four. My answer would be A. (-3,-4)
Answer: the term number is 38
Step-by-step explanation:
Let the number of the term be x
The value of the xth term = 488
In an arithmetic sequence, the terms differ by a common difference, d. This means that the difference between two consecutive terms, d is constant.
The formula for the nth term is
Tn = a + (n-1)d
Where
Tn = the nth term of the arithmetic sequence
a = the first term of the arithmetic sequence.
d = common difference.
From the information given,
a = 7
d = 13
We are looking for the xth term.
Tx = 488 = 7 + (x-1)13
488 = 7 + 13x - 13
Collecting like terms on the left hand side and right hand side of the equation,
13x = 488 -7 + 13
13x = 494
x = 38
The value of the 38th term is 488.