NEED HELP ( due tomorrow )

Jesse estimated the weight of his cat to be 15 to be 12 lb the actual weight is 15 what is the percent error

mafiozo [28]

Answer:

t

Step-by-step explanation:

5 0

3 years ago

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Can someone explain inequality using a word problem

aleksandrvk [35]

What is the inequality between these two fractions 1/2 2/4: answer =...so you would write it out like this 1/2=2/4

8 0

3 years ago

I need help - Geometry - 15 points + brainlyist - 1 question -

lara [203]

Answer:

$120 = (15 + 22)x + 4 + 5 \\ 120 - 9 = 37x \\ 111 = 37x \\ x = 111 \div 37 = 3 \\$

$15x + 5 = 3 \times 15 + 5 = 50$

8 0

3 years ago

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If we list all the natural numbers below 20 that are multiples of 7 or 11, we get 7, 11 and 14. The sum of these multiples is 32

velikii [3]

Number of multiples of 7 up to 1337: $\left\lfloor\dfrac{1337}7\right\rfloor=191$
Number of multiples of 11 up to 1337: $\left\lfloor\dfrac{1337}{11}\right\rfloor=121$
Number of multiples of 77 up to 1337: $\left\lfloor\dfrac{1337}{77}\right\rfloor=17$

This means there are $191+121-17=295$ distinct multiples of 7 *or* 11 up to 1337.

The sum of these multiples is

$\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k$

which can be computed using the well-known formula,

$\displaystyle\sum_{k=1}^nk=\dfrac{n(n+1)}2$

So you have

$\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k=7\dfrac{191\times192}2+11\dfrac{121\times122}2-77\dfrac{17\times18}2=197762$

8 0

3 years ago

Can someone please help me with this!?

Katarina [22]

One way of solving this problem can be Heron's formula. It is a formula that allows us to compute the area of a triangle, knowing the length of its three sides.

For the sake of clarity, let's assume that the point in the top-left lies in the origin, and let's call it point A. Then, the "middle" point is point B, and the bottom-right point is point C.

If we fix the coordinate axis with the origin in A, we have the following coordinates for the three points:

$A = (0,0),\quad B = (4,-1),\quad C = (7,-5)$

We can compute the length of any side using the formula for the distance between two points:

$d(P,Q) = \sqrt{(P_x-Q_x)^2 + (P_y-Q_y)^2}$

Plugging the approriate values, we get the following lenghts:

$\overline{AB} = \sqrt{17},\quad \overline{BC} = 5,\quad \overline{AC} = \sqrt{74}$

Now that we have the lengths, we can use Heron's formula: given the side lenghts $a,b,\text{ and } c$ and the semiperimeter $p$ , the area is given by

$A = \sqrt{p(p-a)(p-b)(p-c)}$

If you plug our values, you will get an area of 6.5. So, unless I'm mistaken, none of the answers seem to mach, whereas 7 seems the best approximation.

4 0

3 years ago