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Arlecino [84]
3 years ago
9

(7/22) (44)=2r pls help

Mathematics
2 answers:
patriot [66]3 years ago
8 0

Answer:r=7/7744

move all terms to the left:

(7/22)(44)-(2r)=0

add all the numbers together, and all the variables

-2r+(+7/22)44=0

multiply parentheses

-2r+7/22*44=0

multiply all the terms by the denominator

-2r*22*44+7=0

multiply elements

-1936r*4+7=0

multiply elements

-7744r+7=0

move all terms containing r to the left, all other terms to the right

-7744r=-7

r=-7/-7744

Masteriza [31]3 years ago
3 0
If your trying to find the value of r, it’s 7
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Write the sentence as an equation.<br><br> 260 is equal to d plus 236 ?​
s344n2d4d5 [400]

Answer:

260 = d + 236 or d + 236 = 260

Step-by-step explanation:

Mental Math

7 0
3 years ago
One writer, a group of students measured snowfall totals at their school. This chart shows how many inches of snow the students
tangare [24]

The correct answer is 20.7 inches of snow

Explanation:

The chart registers the total of snowfall at the school, in this, you can observe the total of snow in December was 3.4 inches, while in January the total was 12.3 and in February it was 8.4. Additionally, if you want to know the total during January and February combined the correct process is to add the two numbers. This means 12.3 inches (January) + 8.4 inches (February) = 20. 7 inches (Total in January and February.) Thus, the answer is 20.7 inches of snow.

4 0
3 years ago
MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD
Varvara68 [4.7K]

Answer:

\sf \: Proved \: \angle \: OAD  \:  =  \angle \: OCD

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u>\angle \: OAD  \:  =  \angle \: OCD</u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

\angle \: OBD  \:  =  \angle \: OCD

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

\angle \: OBD  \:  =  \angle \: OAB \\ \angle \: OAB  \:  =  \angle \: OAD (same \: angles) \\ \angle \: OBD  \:  =  \angle \: OAD

Consider above prove as statement B

From Statement A & B we can say that

\angle \: OAD  \:  =  \angle \: OCD

<em>Thanks for joining brainly community!</em>

5 0
2 years ago
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Kryger [21]

Answer:

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4 0
3 years ago
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azamat

Answer:

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