What is the order and angle of rotation symmetry of a regular octagon?
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Answer:
x^2+y^2+z^2-10x-6y-10z +50 =0
Step-by-step explanation:
Given that a sphere is contained in the first octant
Centre of the sphere is given as (5,3,5)
Since this is contained only in the first octant radius should be at most sufficient to touch any one of the three coordinate planes
When it touches we can get the maximum sphere
We find that y coordinate is the minimum of 3 thus radius can be atmost 3 so that then only it can touch y =0 plane i.e. zx plane without crossing to go to the other octants.
Hence radius =3
Equation of the sphere would be