Answer:
3.825 kg apples.
Step-by-step explanation:
Let x kg be the amount of apples stand owner had initially.
We have been given that during the first hour of operation the farm stand owner sold 15% of the apples he had. Then the amount of sold apples will be:
On the second hour he sold 20% of the remaining apples. So the amount of sold apples on the second hour will be 20% of 0.85x.
During the second hour 25.5 kg of apples were sold, so we can set up an equation as:
So, stand owner had initially 150 kg of apples.
On the third hour he sold 25% of the remaining apples. So the amount of sold apples on the 3rd hour will be 25% of 0.68x
As remaining apples were sold 5% more each following hour.
Let us substitute x=150 into above equation we will get,
Therefore, 3.825 kg of apples were sold during the 4th hour.
Answer:
x>−7
Step-by-step explanation:
left side:
-8(x-3)+5x
distribute -8 into (x-3)
-8x+24+5x
combine like terms
-3x+24
right side:
9(x+12)
distribute 9 into (x+12)
9x+108
-3x+24<9x+108
Subtract 24 on both sides
-3x< 9x+108-24
combine like terms
-3x<9x+84
Subtract 9x on both sides
-3x-9x<+84
combine like terms again
-12x<84
Multiply both sides by -1 (reverse the inequality)
(-12x)(-1)>84(-1)
12x>-84
divide both sides with 12
x>−7
hope this helps
Given a quadratic equation
1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.
In our case the coefficient of x is 10, so we write 10 as 2*5
2. then we write +
and -
to the expression:
Answer: