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2 years ago

Which theorem can you use to show TVR is congruent SRV? SAS, AAS, ASA or SSS?

Mathematics

1 answer:

GalinKa [24]2 years ago

7 0

Answer:

ASA RULE

Step-by-step explanation:

As 2 angles are given and RV is common in both trianlges hence TVR is congruent to SRV by ASA rule

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Area of square floor is 100 square centimeters,and the scale of the drawing is 1 centimeter:2ft,what is the area of the actual f

Taya2010 [7]

100 square centimeters means the dimensions are 10x10
but the actual floor will be 1cm:2ft
so 10cm=20feet
making the dimensions 20feetx20feet
the area of the actual floor is 400 feet

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2 years ago

3/10 of the students in art class are painting with watercolors. 1/2 of the students are painting with oil paints. What fraction

klasskru [66]

8/10 of the students in the art class are painting.
1/2=5/10
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2 years ago

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a florist makes 24 bouquets she uses 16 flowers for each bouquet altogether how many flowers does she use?

NNADVOKAT [17]

Answer:

384

Step-by-step explanation:

24 bouquets * 16 flowers = 384 flowers

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2 years ago

How many solution does an equation have when you isolate the variable and it equals a constant

RoseWind [281]

Answer:

Step-by-step explanation:

it depends. if (for example) y=x2 then there are an infinite amount of answers. if there is an equation like: If (variable X)= (variable Y) + 5 and if X=5, what is Y? then there is only one answer. check an algebra book, it can give you a more detailed answer.

5 0

2 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

2 years ago

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