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Vera_Pavlovna [14]

3 years ago

8

Wilma can mow a lawn in 120 minutes. Rocky can mow the same lawn in 80 minutes. How long does it take for both Wilma and Rocky t

o mow the lawn if they are working together?

1 answer:

saw5 [17]3 years ago

8 0

Work in the rates / minute
wilma:- in 120 minutes she mows 1 lawn
so in 1 minute she mows 1/120 lawn

similarly, Rock mows 1/80 lawn in 1 minute

working together 1/120 + 1/80 = 1/x where x is number of minutes working together

1/20 + 1/80 = 1/48

so 1/x = 1/48

x = 48

answer is 48 minutes

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2 years ago

An airplane must clear a 60-foot pole at the end of a runway 500 yards long determine the angle of elevation at which the airpla

Marat540 [252]

Answer:

2.3 degrees.

Step-by-step explanation:

Please find the attachment.

We are told that an airplane must clear a 60-foot pole at the end of a runway 500 yards long.

Let us convert 500 yards to feet.

1 yard= 3 feet.

500 yards= 3*500 feet= 1500 feet.

We can see from our attachment pole and runway are in form of a right triangle. The pole is opposite to angle of elevation of plane and length of runway is adjacent.

Since tangent represents the relation between opposite and adjacent of right triangle, So we will use tangent to find angle of elevation that plane must ascend to clear the pole.

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$\theta=\tan^{-1}(\frac{60}{1500} )$

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Therefore, the airplane must ascend 2.3 degrees to clear the pole.

8 0

2 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

<u>Area of triangle ABD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

<u>Area of triangle BCD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

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Answer

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Step-by-step explanation:

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2 years ago