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2 years ago

11

Rory played 9 holes of golf. On each hole took 4 strokes to get his ball in the hole. Choose Yes or no to tell if each equation

can be used to find the total number of strokes it took Rory to complete 9 holes.

1 answer:

Rashid [163]2 years ago

3 0

Answer:

what are the equation options???

Step-by-step explanation:

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A segment has an endpoint at (1,−2). The midpoint is at (−4,−2). What are the coordinates of the other endpoint?

vodka [1.7K]

Answer:

The other midpoint is located at coordinates (-9,-2) (Second option)

Step-by-step explanation:

<u>Midpoints</u>

If P(a,b) and Q(c,d) are points in $\mathbb{R} ^2$ , the midpoint between them is the point exactly in the center of the line that joins P and Q. Its coordinates are given by

$\displaystyle x_m=\frac{a+c}{2}$

$\displaystyle y_m=\frac{b+d}{2}$

We are given one endpoint at P(1,-2) and the midpoint at M(-4,-2). The other endpoint must be at an equal distance from the midpoint as it is from P. We can see both given points have the same value of y=-2. This simplifies the calculations because we only need to deal with the x-coordinate.

The x-distance from P to M is 1-(-4)=5 units. This means the other endpoint must be 5 units to the left of M:

x (other endpoint)= - 4 - 5 = - 9

So the other midpoint is located at (-9,-2) (Second option)

5 0

2 years ago

Is this a right triangle?

vesna_86 [32]

Answer:

yes!

Step-by-step explanation:

if it has a 90° angle it is a right triangle :)

8 0

2 years ago

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Find the area of the figure.

blondinia [14]

I hope this helpssss :))

5 0

1 year ago

Solve for m and n using the special right triangles

Irina18 [472]

Since this is a 45-45-90 triangle, n = 6 and m = 6√3.

I hope this helps!

8 0

3 years ago

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

Read 2 more answers