If q represents the quantity of solution needed, you require
... 0.90q = 0.15×(100 mL)
... q = (0.15/0.90)×(100 mL)
... q ≈ 16.7 mL
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You actually need 16 2/3 mL of concentrated solution.
Add 4x to both sides of the equation to get the equation into a form that can be graphed. rearrange the equation to regular form into y= -x^2 -4x +7 and put it into ur graphing calculator. look for the halfway of the parabola that would fold it in half
Answer:
11.547 ft wide by 5.774 ft high
769.800 ft³ capacity
Step-by-step explanation:
Volume is maximized for a given area by having the area of a pair of opposite sides equal the area of the bottom. That means the overall area of the container is 3 times the area of the bottom. Then the square bottom will have a width of ...
w = √(400/3) ≈ 11.547 . . . feet
The height is half that, so is ...
h = w/2 = 11.547/2 ≈ 5.774 . . . feet
The capacity is then ...
w²h = (11.547 ft)²(5.774 ft) = 769.800 ft³
The container is 11.547 ft wide by 5.774 ft high. It has a capacity of 769.800 cubic feet.
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You want to maximize w^2h subject to w^2 + 4wh = 400. Solving the constraint equation for h, we get h = (400 -w^2)/(4w) and the volume we want to maximize can be written as ...
V = w(400-w^2)/4
This will be an extreme when dV/dw = 0, so we want to solve ...
dV/dw = 0 = 100 -(3/4)w^2
w^2 = 400/3
w = √(400/3) . . . . . as above
Answer:
he ratio of cups of mixed nuts to cups of granola is 1/12
Step-by-step explanation:
