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Alona [7]
3 years ago
14

A book has been discounted by 30%. It is on sale for $22.40. Find the original price.

Mathematics
1 answer:
Harrizon [31]3 years ago
8 0
ANSWER: $29.12 is the original price

EXPLANATION:
Do 22.40 • 0.30 to get 6.72
Then take 6.72 and add it to 22.40
This gives you the original price, $29.12


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There are 5 students on the school chess team. They need to raise at least $445 for a field trip. Their advisor says they have r
lara31 [8.8K]

Answer: he was wrong. Each student will have to pay $76.54 at least

Step-by-step explanation:

They need to raise at least $445 for a field trip. This means that the amount to be raised should be greater than or equal to $445

Their advisor says they have raised 14% of the funds so far. This means that the amount that they have raised so far is

14/100 × 445 = 0.14×445=$62.3

The amount of money left for them to raise is total amount of money needed - 14% that they have raised so far. It becomes

445 - 62.3 = $382.7

she wants each of them to raise an equal share of the money still needed. There are 5 students on the school chess team. This means that 5 students would be raising $382.7 equally.

The leat amount of money, m that each student will have to pay is

m = 382.7/5=76.54

He solves his inequality and says the solution is m?$12.46. He got it wrong

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What is the approximation for 78.8×6.8
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Describe fully the single transformation which takes shape A to shape B
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Clockwise rotation of 90 degress around the point (4,3)

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What is the value of y?<br><br> Enter your answer in the box.<br><br> y =
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Because of Theorem 5.47 any function that is continuous on (0, 1) but unbounded cannot be uniformly continuous there. Give an ex
almond37 [142]

Answer:

f: (0,1) \to \mathbb{R}

f(x) = \sin(1/x)

Step-by-step explanation:

<u>f is continuous</u> because is the composition of two continuous functions:

g(x) = \sin(x) (it is continuous in the real numbers)

h(x) = 1/x (it is continuous in the domain (0,1))

<u>It is bounded</u> because -1 \leq \sin(\theta) \leq 1

<u>And it is not uniformly continuous</u> because we can take \varepsilon = 1 in the definition. Let \delta > 0 we will prove that there exist a pair x,y\in \mathbb{R} such that |x-y|< \delta and |f(x) -f(y)|> \varepsilon = 1.

Now, by the archimedean property we know that there exists a natural number N such that

\frac{1}{N} < 2\pi \delta

\Rightarrow \frac{1}{2\pi N} < \delta.

Let's take x = \frac{1}{2\pi N + \pi/2} and y = \frac{1}{2\pi N + 3\pi/2}. We can see that

|x-y| = \frac{1}{2\pi N + \pi/2}-\frac{1}{2\pi N + 3\pi/2}

And also:

|f(x)- f(y)| = |f(2\pi N + \pi/2) - f(2\pi N + 3\pi/2)| = |1 - (-1)| = 2 > \varepsilon

And we conclude the proof.

8 0
3 years ago
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