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Dahasolnce [82]
3 years ago
12

Figure ABCD is a parallelogram What are the lengths of line segments AB and BC?

Mathematics
1 answer:
Olegator [25]3 years ago
8 0

Question is Incomplete,Complete question is given below;

Figure ABCD is a parallelogram.

What are the lengths of line segments AB and BC?

AB = 4; BC = 16

AB = 4; BC = 8

AB = 10; BC = 20

AB = 10; BC = 28

Answer:

AB = 10 ;BC =28.

Step-by-step explanation:

The Diagram is missing in the question we have attached the diagram for your reference.

Given:

AB = 3y -2

DC = y+6

BC = x+12

AD = 2x-4

We need to find the lengths of AB and BC.

Solution:

Since given that Figure ABCD is a parallelogram.

"The opposite side of parallelogram are equal."

Hence we can say that;

AB = DC

Substituting the value we get;

3y-2=y+6

Combining the like terms we get;

3y-y=6+2\\\\2y =8

Dividing both side by 2 we get;

\frac{2y}{2}=\frac{8}{2}  \\\\y=4

Now AB = 3y -2 =3\times 4-2 =12-2 =10

Also

BC = AD

Substituting the value we get;

x+12=2x-4

Combining the like terms we get;

2x-x=12+4\\\\x =16

Now BC = x+12 =16+12 =28

Hence AB = 10 and BC =28.

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Find an equation of the line parallel to 8x − 3y = 1 and containing the point (−2, 0)
Anna007 [38]

The equation of the line parallel to 8x − 3y = 1 and containing the point (−2, 0) is 8x -3y = -16

<h3>Equation of a straight line</h3>

From the question, we are to determine the equation of the line parallel to the given equation and that passes through the given point

Lines that are parallel to each other will have the same slope.

First, we will determine the slope of the line in the given equation.

The given equation of the line is

8x − 3y = 1

Express the equation in the slope-intercept form of a line, y = mx + b

Where m is the slope and

b is the y-intercept

That is,

8x − 3y = 1

8x -1 = 3y

3y = 8x - 1

y = 8/3(x) - 1/3

By comparing,

∴ The slope of the line is 8/3

Since we are to find the equation of a line parallel to this, the slope of the line will also be 8/3

Now, find the equation of a line containing the point (-2, 0) and that has  a slope of 8/3

Using the point-slope form of a line

y - y₁ = m(x - x₁)

x₁ = -2

and y₁ = 0

∴ y - 0 = 8/3(x - -2)

y = 8/3(x +2)

3y = 8(x +2)

3y = 8x + 16

8x -3y = -16

Hence, the equation of the line parallel to 8x − 3y = 1 and containing the point (−2, 0) is 8x -3y = -16

Learn more on Equation of a line here: brainly.com/question/13763238

#SPJ1

5 0
2 years ago
I need help like right now!!
vladimir2022 [97]

Step-by-step explanation:

A(2,0)=A'(2,0)

B(4,-1)=B'(0,0)

C(1,-3)=C'(2,3)

4 0
3 years ago
enter your answer and show all the steps that you use to solve this problem in the space provided. if x+3/3 = y+2/2, then x/3 =
tatuchka [14]

Answer: y/2

Step-by-step explanation:

Since the x would equal to 3’s and the y equals to 2’s then it would basically be simplified to y/2

3 0
4 years ago
A dolphin was swimming 20 feet below the surface of the water. It descended 8 feet to catch a fish. What integer represents its
Nimfa-mama [501]
-28. It’s underwater which is -20 and went -8 more feet down.
3 0
4 years ago
What is the area of Δ STR?
Rufina [12.5K]
Answer:  The area of the triangle is:  " 30 ft.² " .
_____________________________________________________
Explanation:
→ A = " 30 ft.² " .
_____________________________________________________
Area of a triangle, "A" = 1/2 * (base length) * (perpendicular height) ; 

that is: 

" A = (1/2) * b * h " ; 

→ A = (1/2) * (6 ft) * (10 ft) ;  ←  Plug in the given values from the "diagram" ; 
 
        = (3 ft) * (10 ft) ; 
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→ A = " 30 ft.² " .
______________________________________________________ 
6 0
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