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Readme [11.4K]
4 years ago
9

What is the area of Δ STR?

Mathematics
1 answer:
Rufina [12.5K]4 years ago
6 0
Answer:  The area of the triangle is:  " 30 ft.² " .
_____________________________________________________
Explanation:
→ A = " 30 ft.² " .
_____________________________________________________
Area of a triangle, "A" = 1/2 * (base length) * (perpendicular height) ; 

that is: 

" A = (1/2) * b * h " ; 

→ A = (1/2) * (6 ft) * (10 ft) ;  ←  Plug in the given values from the "diagram" ; 
 
        = (3 ft) * (10 ft) ; 
______________________________________________________
→ A = " 30 ft.² " .
______________________________________________________ 
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Answer:

15 pounds

Step-by-step explanation:

because half of 42 is 21-6 is 15 therefore it all adds up to 42

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3 years ago
Solve the linear differential equation 2xy' + y = 2√x
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Answer:

Step-by-step explanation:

General form of the linear differential equation can be written as:

\frac{dy}{dx}+P(x)y=Q(x)

For this case, we can rewrite the equation as:

\frac{dy}{dx}+\frac{1}{2x}y=\frac{\sqrt{x}}{x}

Here P(x) =\frac{1}{2x}; Q(x)=\frac{\sqrt{x}}{x}

To find the solution (y(x)), we can use the integration factor method:

Fy(x)=\int Q(x)Fdx+C \rightarrow F=e^{\int P(x)dx

Then F=e^{\int \frac{1}{2x}dx}=e^{\frac{1}{2}\ln|x|\right}=\sqrt{|x|}

So, we can find:

y\sqrt{|x|}=\int \frac{\sqrt{x}\sqrt{|x|}}{x}dx+C

Suppose that x\in \double R, then \sqrt{|x|}=\sqrt{x} , and we find:

y\sqrt{x}=x+C \rightarrow y(x)=\sqrt{x}+\frac{C\sqrt{x}}{x}

To check our solution is right or not, put your y(x) back to the ODE:

y' = \frac{1}{2\sqrt{x}}-\frac{C}{2\sqrt{x^{3}}}

2xy'=\frac{x-C}{\sqrt{x}}

2xy'+y=\frac{x-C}{\sqrt{x}}+\sqrt{x}+\frac{C\sqrt{x}}{x}=2\sqrt{x}

(it means your solution is right)

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2 years ago
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Step-by-step explanation:

4 0
3 years ago
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satela [25.4K]

Answer:

Option b.

Step-by-step explanation:

Given : \Delta SRQ is right angled triangle . An altitude is drawn from point R to point T on side S Q to form a right angle. The length of S T is 9 and the length of T Q is 16. The length of S R is x.

In the figure, \angle SRQ=90^{\circ} and RT is perpendicular to SQ.

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8 0
3 years ago
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