How do I find the dimensions of three different rectangles with the area of 6 cm^2

1 answer:

6 0

The area of a rectangle is (length) times (width).
So you have to find a pair of numbers that multiply to produce 6 .

If you only stick to whole numbers, then I don't think there are three
different ones. You're going to need one pair that multiply to 6 and
are not both whole numbers.

After I explain how to solve problems, I hate to give answers. But with
all due respect, I have a feeling that I haven't nudged you enough yet
for you to use my explanation to find the answers on your own.
So here are some answers:

1 and 6
2 and 3

and sets of dimensions that are not both whole numbers, like

0.6 and 10
1.2 and 5
1.25 and 4.8
1.5 and 4
2.4 and 2.5

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I need help with this please :)

Marina CMI [18]

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Answer:

all are Not Equivalent

Step-by-step explanation:

The coefficient of t³ in the target expression is -3. In order for that to be the result of simplifying any of the given expressions, they must have ( )^(t^3) in the denominator. None do, so none of the offered choices is equivalent to the given expression.

_____

The expressions simplify like this:

$\dfrac{(2^3)^{t^3}}{2^{5t}}=2^{3t^3-5t}\\\\\dfrac{8^{t^3}}{32^t}=2^{3t^3-5t}\\\\8^{t^3}\cdot32^t=2^{3t^3+5t}$