Answer:
(b) 
Step-by-step explanation:
1 male named Bart (b)
3 females named Charlene(c), Diana(d), and Erin(e).
Since there is replacement, the possible samples are:
bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.
Total Number of pairs = 16
Event of picking 2 males:bb
Event of 1 male:bc,cb,bd,db,be,eb
Event of picking 0 males:
cc, cd, ce, dc, dd, de, ec, ed, and ee.

b. The mean of the sampling distribution

c. No; the proportion of males is
while the mean is
.
B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.