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Anna [14]
3 years ago
14

There were n signers of the Declaration of Independence. The youngest was Edward Rutledge, who was x years old. The oldest was B

enjamin Franklin, who was y years old. X is 25% of 104, 7 is 10% of y, and n is 80% of y. Y is what percent of (n+y-x)?
Mathematics
2 answers:
Lina20 [59]3 years ago
5 0
X = .25 x 104 X=26
Y= 7/.10 Y=70
N= .8 x 70 N=56
n+y-x 56+70-26=100

70/100 = .7 or 70%
The answer is: Y is 70% of (n+y-x)

jeyben [28]3 years ago
4 0

Answer:

70%

Step-by-step explanation:

First we calculate X using the following formula:

X = 25/100 * 104

X = 0.25 * 104

X = 26

Then we calculate Y using the following formula:

7 = 10/100 * Y

7 = 0.1 * Y

7/0.1 = Y

Y = 70

Then we calculate N as per the formula below:

N = 80/100 * Y

N = 0.8 * 70

N = 56

Finally using the formula mentioned in question we derive Y what percent of N + Y - X:

= Y/ (N + Y - X) * 100

= 70/ (56 + 70 - 26) * 100

= 70/100 * 100

= 70%

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Step-by-step explanation:

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Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.
Flauer [41]

Answer:

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

Step-by-step explanation:

Given

\sqrt{128a^{6}b^{13}}

Required

Solve

\sqrt{128a^{6}b^{13}}

The expression can be split to:

\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}

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Rewrite as:

\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2}  * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

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Step-by-step explanation:

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