A runner is 7/8 mile from the finish line. If she can travel 3/8 mile per minute, how long will it take her to finish the race?

Mathematics

1 answer:

slavikrds [6]4 years ago

7 0

About 2 minutes and 33 seconds?
[ I apologize if this is wrong ]

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Find the area of a trapezoid with base 1 side = 10 base 2 side = 16 and 3

mart [117]

Answer:

Area of Trapezoid is 39 unit²

Step-by-step explanation:

Given as :

For A Trapezoid

The measure of base side 1 = $b_1$ = 10 unit

The measure of base side 2 = $b_2$ = 16 unit

The height of the Trapezoid = h = 3 unit

Let The Area of Trapezoid = A square unit

<u>Now, From Formula</u>

Area of Trapezoid = $\dfrac{1}{2}$ × (sum of opposite base) × height

I.e A = $\dfrac{1}{2}$ × ( $b_1$ + $b_2$ ) × h

Or, A = $\dfrac{1}{2}$ × (10 unit + 16 unit) × 3 unit

Or, A = $\dfrac{1}{2}$ × (26 unit) × 3 unit

Or, A = $\dfrac{1}{2}$ × 78 unit²

Or, A = $\dfrac{78}{2}$ unit²

I.e A = 39 unit²

So, The Area of Trapezoid = A = 39 unit²

Hence, The Area of Trapezoid is 39 unit² . Answer

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A new baby is born in France the newspaper reports the baby's mass to be 1.5×10³ kg

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The question only supplied us with the mass of the new baby which is:

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How does the graph of f(x)=3lx+2l+4 relate to its parent function?

Sergeeva-Olga [200]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units

check the picture below