All categories

3 years ago

A runner is 7/8 mile from the finish line. If she can travel 3/8 mile per minute, how long will it take her to finish the race?

Mathematics

1 answer:

slavikrds [6]3 years ago

7 0

About 2 minutes and 33 seconds?
[ I apologize if this is wrong ]

You might be interested in

the area of a circular pool cover is 314 square feet. Write & solve an equation to find the diameter of the pool cover

Hunter-Best [27]

I'll help you but I;m not just going to give you the answer

8 0

3 years ago

Find the equivalent fraction for 10/20

dezoksy [38]

$\frac{10}{20} = \frac{ \frac{10}{10} }{ \frac{20}{10} } = \frac{1}{2}$

6 0

3 years ago

For art class, each student

Mars2501 [29]

Answer:

s=25

Step-by-step explanation:

3 0

3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

Simplify:<br>(ay<br>8<br>6.<br>5x - 25 30 - 6x

maw [93]

Answer:

-x - 2530

Step-by-step explanation:

5x - 2530 - 6x

5x - 6x = -x

-x - 2530

6 0

3 years ago

Read 2 more answers