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MaRussiya [10]
3 years ago
8

$#4 Find the value of x. Round answer to nearest tenth.

Mathematics
1 answer:
shusha [124]3 years ago
5 0

Answer:

Step-by-step explanation:

From the given right angle triangle,

The hypotenuse of the right angle triangle is x

With m∠54 as the reference angle,

The unknown is the adjacent side of the right angle triangle.

The opposite side of the right angle triangle is 19

To determine x, we would apply the Sine trigonometric ratio.

Sine θ = opposite side/hypotenuse. Therefore,

Sin 54 = 19/x

x = 19/Sin54 = 19/0.809

x = 23.5 to the nearest tenth.

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Brady has $180 and makes $6 an hour. Nick has no money but makes $8 an hour.
a_sh-v [17]

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2 years ago
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Determine if the sequence below is arithmetic or geometric and determine the common difference/ratio in simplest form.
Nana76 [90]

Step-by-step explanation:

this is clearly not a linear sequence (the terms don't have the same difference).

so, it has to be a geometric sequence.

the common ratio is r.

s2 = s1 × r

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2 years ago
What is the midpoint of the line segment with endpoints of (-2,-2) and (4,6)?
slamgirl [31]

Answer:

option (d) is correct.

The mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Step-by-step explanation:

Given: end points of a line segment as (-2,-2) and (4,6)

We have to find the mid points of the line segment whose ends points are given.

Mid point formula is stated as ,

For a line having end points as \left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right) , the mid point can be calculated as,

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here,

\left(x_1,\:y_1\right)=\left(-2,\:-2\right),\:\left(x_2,\:y_2\right)=\left(4,\:6\right)

Substitute in mid point formula, we get,

=\left(\frac{4-2}{2},\:\frac{6-2}{2}\right)

Solving further , we get,

=\left(1,\:2\right)

Thus, the mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Thus, option (d) is correct.

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3 years ago
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