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marysya [2.9K]
3 years ago
15

Please help me with this i need this grade

Mathematics
1 answer:
Wittaler [7]3 years ago
5 0

Answer: B/The second answer

Step-by-step explanation:

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There are 75 students enrolled in camp. The day before the camp begins, 8℅ of the students cancel. how many students actually at
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69 kids still attend
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Suppose a continuous probability distribution has an average of μ=35 and a standard deviation of σ=16. Draw 100 times at random
yulyashka [42]

Answer:

To use a Normal distribution to approximate the chance the sum total will be between 3000 and 4000 (inclusive), we use the area from a lower bound of 3000 to an upper bound of 4000 under a Normal curve with its center (average) at 3500 and a spread (standard deviation) of 160 . The estimated probability is 99.82%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we have that the mean is \mu*n and the standard deviation is s = \sigma \sqrt{n}

In this problem, we have that:

\mu = 100*35 = 3500, \sigma = \sqrt{100}*16 = 160

This probability is the pvalue of Z when X = 4000 subtracted by the pvalue of Z when X = 3000.

X = 4000

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{4000 - 3500}{160}

Z = 3.13

Z = 3.13 has a pvalue of 0.9991

X = 3000

Z = \frac{X - \mu}{s}

Z = \frac{3000 - 3500}{160}

Z = -3.13

Z = -3.13 has a pvalue of 0.0009

0.9991 - 0.0009 = 0.9982

So the correct answer is:

To use a Normal distribution to approximate the chance the sum total will be between 3000 and 4000 (inclusive), we use the area from a lower bound of 3000 to an upper bound of 4000 under a Normal curve with its center (average) at 3500 and a spread (standard deviation) of 160 . The estimated probability is 99.82%.

5 0
3 years ago
Need help on this question
Sedaia [141]

Answer:

A

Step-by-step explanation:

Hey There!

So these triangles are congruent so segment CD is equal to segment DB

so to find x we use the equation

7x+10=10x+7

now we solve for x

step 1 subtract each side by 7

10-7=3

7-7 cancels out

now we have 7x+3=10x

step 2 subtract each side by 7 x

10x-7x=3x

7x-7x= cancels out

now we have

3x=3

step 3 divide each side by 3

3/3=1

3/3 cancels out

now we have

x=1

3 0
2 years ago
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bearhunter [10]

Answer:

The grinding of the material

Step-by-step explanation:

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How much interest is earned on $2,700 in one year if it is invested at 3%?
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$81 is earned by investing $2700 in one year at 3%.
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