Answer:
y= 2,75
Step-by-step explanation:
6 = 3 + 5 (y-2)
6=8(y-2)
6/8=y-2
¾=y-2
0,75+2=y
y= 2,75
Answer:
20
Step-by-step explanation:
y^2+4y-1=(-7)^2+4(-7)-1=(-7)(-7)-28-1=49-28-1=21-1=20
Given:
Volume of a cube = 27,000 in^3
(Note: A cube has equal sides)
The volume of a cube = a^3
So,
![\begin{gathered} 27000=a^3 \\ \sqrt[3]{27000}\text{ = a} \\ a\text{ = 30 in.} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2027000%3Da%5E3%20%5C%5C%20%5Csqrt%5B3%5D%7B27000%7D%5Ctext%7B%20%3D%20a%7D%20%5C%5C%20a%5Ctext%7B%20%3D%2030%20in.%7D%20%5Cend%7Bgathered%7D)
Therefore, the lenght of one side is 30 inches.
Answer: See explanation
Step-by-step explanation:
Here is the complete question:
A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers.
A. Students: 72
Minimum of chaperones: 9
B. Students: 16
Minimum of chaperones: 2
C. Students: 60
Minimum of chaperones: 6
D. Students: 45
Minimum of chaperones: 5
E. Students: 40
Minimum of chaperones: 8
Since the museum requires a minimum of 3 chaperones for a field trip with 24 students. This means that there will be 24/3 = 8 students per chaperone.
We then divide the number of students given in the question by the number of chaperone to know our answers. This. Will be:
Students: 72
Minimum of chaperones: 9
This will be: 72/9 = 8
Therefore, this is correct.
B. Students: 16
Minimum of chaperones: 2
This will be: 16/2 = 8
This is correct
C. Students: 60
Minimum of chaperones: 6
This will be: = 60/6 = 10.
Therefore, this is wrong
D. Students: 45
Minimum of chaperones: 5
This will be 45/5 = 9
Therefore, this is wrong.
E. Students: 40
Minimum of chaperones: 8
This will be: 40/5 = 8.
Therefore, this is wrong.
Therefore, options A and B are correct.
Answer:
volume = length^3
3375= length^3
therefore length = 15 units