A) 2/3 divided by 5/1
= 2/3 X 1/5
= 2/15 of the book
B) 14X5=70
1/3
2/3
3/3
70+35= 105 pages
49^(3/2)
This is the same as (sqrt49)^3
7^3 = 343
The total number of possible combinations from flipping a coin 10 times is 2^10 = 1024.
I believe the answer is A because its the only one that makes the most sense.
in3