Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 38 feet
1 answer:
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Answer: About 3.06
Step-by-step explanation:
We can use trigonometry functions to solve for AC. Let the ?, representing AC, be "x" in our mathematical work.
Since we have the hypotenuse and x is adjacent to the angle given, I am going to use cosine.
cos(θ) =
cos(40) =
0.766 ≈
3.06 ≈ x
x ≈ 3.06