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saveliy_v [14]
3 years ago
7

What does AC=? Round your answer to the nearest hundredth. Please help

Mathematics
1 answer:
faltersainse [42]3 years ago
4 0

Answer: About 3.06

Step-by-step explanation:

  We can use trigonometry functions to solve for AC. Let the ?, representing AC, be "x" in our mathematical work.

  Since we have the hypotenuse and x is adjacent to the angle given, I am going to use cosine.

      cos(θ) = \frac{adjacent}{hypotenuse }

      cos(40) = \frac{x}{4}

      0.766 ≈ \frac{x}{4}

      3.06 ≈ x

      x ≈ 3.06

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PLEASE I NEED HELP RN!!!
Dmitrij [34]

9514 1404 393

Answer:

  (1.43, 1.87)

Step-by-step explanation:

The formula for the incenter requires we know the lengths of the sides of the triangle. These are found using the distance formula.

  BC = √((4-3)^2 +(5+1)^2) = √37

  AC = √((-4-3)^2 +(2+1)^2) = √58

  AB = √((-4-4)^2 +(2-5)^2) = √73

Then the incenter is ...

  (A(BC) +B(AC) +C(AB))/(BC +AC +AB)

  ≈ (6.08276(-4, 2) +7.61577(4, 5) +8.54400(3, -1))/22.2425

  ≈ (1.42808, 1.87480)

Rounded to hundredths, the incenter is (1.43, 1.87).

4 0
3 years ago
What is equivalent to 5 to the 2nd power times 5 to the 2nd power
adelina 88 [10]

<em>5 to the 2nd power times 5 to the 2nd power is equivalent to 625</em>

<h2>Explanation:</h2>

In this case, we have the following statement:

<em>5 to the 2nd power times 5 to the 2nd power. </em>In a mathematical language:

5^2\times 5^2

From product rules, we know that:

a^n \cdot a^m=a^{n+m}

Applying this rule to our problem:

5^2\times 5^2=5^{2+2}=5^4=625

<em>5 to the 2nd power times 5 to the 2nd power is equivalent to 625</em>

<h2>Learn more:</h2>

Rules of exponents: brainly.com/question/12140557

#LearnWithBrainly

3 0
4 years ago
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Step-by-step explanation:

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Sorry if it’s incorrect ;-;

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An airplane flying at an altitude of 2600 m is approaching an airport run away located 56 km away (from the airplane to the run
Brrunno [24]

Given :

An airplane flying at an altitude of 2600 m is approaching an airport run away located 56 km away.

To Find :

The airplane’s angle of decent.

Solution :

Height of plane, h = 2600 m.

Horizontal distance of airplane from vertices is, d = 56 km = 56000 m.

Let, angle of depression is Ф.

So,

tan \ \phi = \dfrac{56000}{2600}\\\\tan \ \phi = 21.54\\\\\phi = 87.34^o

Therefore, the angle of decent is 87.34°.

Hence, this is the required solution.

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