Answer:
Theorem : Opposite sides of a parallelogram are congruent or equal.
Let us suppose a parallelogram ABCD.
Given: and (According to the definition of parallelogram)
We have to prove that: AB is congruent to CD and BC is congruent to AD.
Prove: let us take two triangles, and
In these two triangles, { By the definition of alternative interior angles}
Similarly,
And, AC=AC (common segment)
By ASA,
thus By the property of congruent triangle, we can say that corresponding sides of are also congruent.
Thus, AB is congruent to CD and BC is congruent to AD.
Step-by-step explanation:
The answer is : Prism
hope this helps !
Which ever graph looks like this
Answer:
46
Step-by-step explanation:
The n th term of an AP is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here d = - 3 and 
= - 5 , thus
a₁ + (17 × - 3) = - 5
a₁ - 51 = - 5 ( add 51 to both sides )
a₁ = 46
