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3 years ago

Please help which graph

Mathematics

1 answer:

katen-ka-za [31]3 years ago

5 0

Which ever graph looks like this

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Will mark branniest if gotten right

iris [78.8K]

Answer:

? = 30°

Step-by-step explanation:

All angles in a triangle add up to 180°

? + 130° + 20° = 180°

? = 180° - 130° - 20°

? = 30°

8 0

3 years ago

ASAP NEEDED Which expression does the graphic represent? 8 positive tiles. 1 tile is crossed out. 7 minus 1 7 minus (negative 1)

seropon [69]

Answer:

8-1

Step-by-step explanation:

I know things : )

4 0

3 years ago

Read 2 more answers

A customer buys 15.5 cheese pizzas which are $10.50 each. What is the total? Round it to the nearest hundredth.

Cerrena [4.2K]

First of all, how do you buy exactly 15.5 pizzas?
what is a 0.5 pizza?

anyway

cost=cost per pizza times number of pizzas
cost per pizza=10.50
number of pizzas=15.5

cost=10.50 times 15.5
cost=162.75

total cost is $162.75

5 0

3 years ago

WILL MARK BRINLIEST. Can someone help me wit den two questions?

VLD [36.1K]

Answer:1. B 2. D

Step-by-step explanation:

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3 years ago

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A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c

Alenkinab [10]

Answer:

$C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}$

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

$l\times b\times h$

where l is the length, b is the base and h is the height.

Volume of box =

$s^2h = 150\\\\h = \dfrac{150}{s^2}$

Area of base =

$\text{side}\times \text{side} = s^2$

Cost of concrete for the base = $4

Cost of base($) = $4s^2$

Area of roof =

$\text{side}\times \text{side} = s^2$

Cost of material for the roof = $2

Cost of roof ($) = $2s^2$

Area of 4 walls =

$4\times (sh)\\=4sh$

Cost of material for the side = $2.50

Cost of material of side($) =

$2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}$

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

$C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}$

is the required cost function.

5 0

3 years ago