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OleMash [197]
3 years ago
15

which of the following can be deduced from the periodic table? a.many physical properties of elements. b. distribution of variou

s isotopes. c. time of discovery. d. age of a sample of elements
Chemistry
1 answer:
I am Lyosha [343]3 years ago
4 0

Answer:

Many physical properties

Explanation:

  • The periodic table of elements arranges elements into columns called groups and rows called periods.
  • Elements in the same period have the same number of energy levels while those in the same group share similar chemical properties.
  • From the periodic table, one can deduce many physical properties of elements. For example, the physical state, the valence electrons, atomic radius, etc.
  • Elements in the same group have the same number of valence electrons and as you go down the group the energy levels increase thus increasing the atomic radius.
  • Additionally, from the periodic table, one can identify whether an element is a metal, non-metal or a metalloid.
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Multiply 3 by the atomic mass of fluorine, forgive me if I’m wrong
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3 years ago
If a reaction releases 675,000 Joules, how many kcal does it release?
Mamont248 [21]

Answer: If a reaction releases 675,000 Joules then it means it releases 161.328872 kcal.

Explanation:

According to the standard conversion,

1 Joule = 0.000239006 kcal

Therefore, 675,000 Joules will be converted into kcal as follows.

1 Joule = 0.000239006 kcal\\675,000 J = 675000 J \times \frac{0.000239006 kcal}{1 J}\\= 161.328872 kcal

Thus, we can conclude that if a reaction releases 675,000 Joules then it means it releases 161.328872 kcal.

5 0
3 years ago
How many milliliters of concentrated hydrochloric acid solution (36.0% HCl by mass, density = 1.18 g/mL) are required to produce
poizon [28]
W=0.360
p=1.18g/mL
pH=2.12
v=14.0 L
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v₀-?

1) pH=-lg[H⁺]

    [H⁺]=c(HCl)=10^(-pH)

    n(HCl)=v[H⁺]=v*10^(-pH)

2) n(HCl)=m(HCl)/M(HCl)=wv₀p/M(HCl)

3) v*10^(-pH)=wv₀p/M(HCl)

    v₀=v*10^(-pH)M(HCl)/(wp)
  
    v₀=14.0*10^(2.12)*36.46/(0.360*1.18)=9.115 mL


Approximately 9.1 mL of concentrated solution required.




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Explanation:

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