A quantity of water vapor at 100°C is condensed to liquid water at the same temperature. In the process, 180,414.08 joules of
1 answer:
Answer:
0.08kg
Explanation:
Given parameters:
Temperature of water = 100°C
Quantity of heat released = 180414.08J
Unknown:
Quantity of water condensed = ?
Solution:
This is simple phase change process without any attendant change in temperature.
To solve this problem, use the formula below;
H = mL
H is the heat released
m is mass
L is the latent heat of condensation of water = 2260 kJ/kg
Insert the parameters and solve;
180,414.08 = m x 22.6 x 10⁵ J/kg
m = = 0.08kg
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