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drek231 [11]
4 years ago
9

Help with math homework. I'll mark you as brainiest!

Mathematics
1 answer:
lorasvet [3.4K]4 years ago
5 0
For the living room one, you have an 11' wall, & a 2' 6" shelf.
First, we'll divide the length of both in half:
5' 6" wall, 1' 3" shelf
Now, subtract the two:
4' 3"
That's how far away the edge of the shelf needs to be from either corner of the wall to be centered.

For the second one:
We need to get all these numbers into the same formatting. I say we go fraction.
First guy got 13 out of 18
Second guy got .7 (repeating)
Third guy got 5/6
Ok, first, we'll turn .7 repeating into a fraction. This won't always work, because not all decimals will turn into a nice fraction. But this one will.
.7 (repeating) = 7/9
So we have:
13/18
7/9
5/6
Now, we can't compare these quite yet. They all need to have the same denominator. So, what's the LCM of the three denominators? 18, right?
The first one can be left alone, since it has a denominator of 18 already. The second one: multiply both numbers by 2, and we get 14/18. For the third: multiply everything by 3, and we get 15/18.
NOW let's compare them:
Jon: 13/18
Jim: 14/18
Joe: 15/18
It's now clear that Joe got the highest score.
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Yesterday, the price of a can of beans at five supermarkets was $1.92, $2.01,
strojnjashka [21]

Answer:

B. $2.14

Step-by-step explanation:

Given that

The price of the five supermarkets would be $1.92, $2.01,

$1.89, $2.22, and $2.16

And, each supermarket would be increased by $0.10

So, the today mean price would be

= ($1.92 + $2.01 + $1.89 + $2.22 + $2.16 + $0.10 × 5) ÷ (5)

= $10.7 ÷ 5

= $2.14

Therefore the second option is correct

5 0
3 years ago
At an interest rate of 8% compounded annually, how long will it take to double the following investments?
Paladinen [302]
Let's see, if the first one has a Principal of $50, when it doubles the accumulated amount will then be $100,

recall your logarithm rules for an exponential,

\bf \textit{Logarithm of exponentials}\\\\
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
-------------------------------\\\\
\qquad \textit{Compound Interest Earned Amount}
\\\\


\bf A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$100\\
P=\textit{original amount deposited}\to &\$50\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annnually, thus once}
\end{array}\to &1\\
t=years
\end{cases}
\\\\\\
100=50\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 100=50(1.08)^t
\\\\\\
\cfrac{100}{50}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)
\\\\\\


\bf log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\
-------------------------------\\\\


now, for the second amount, if the Principal is 500, the accumulated amount is 1000 when doubled,

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$1000\\
P=\textit{original amount deposited}\to &\$500\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annnually, thus once}
\end{array}\to &1\\
t=years
\end{cases}
\\\\\\
1000=500\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 1000=500(1.08)^t
\\\\\\


\bf \cfrac{1000}{500}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)
\\\\\\
log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\
-------------------------------

now, for the last, Principal is 1700, amount is then 3400,

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$3400\\
P=\textit{original amount deposited}\to &\$1700\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annnually, thus once}
\end{array}\to &1\\
t=years
\end{cases}

\bf 3400=1700\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 3400=1700(1.08)^t
\\\\\\
\cfrac{3400}{1700}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)
\\\\\\
log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t
8 0
4 years ago
Which type of parent function does the equation f(x)= √x represent
il63 [147K]

Answer:

I don't know parents function

Step-by-step explanation:

I don't know parents function

7 0
3 years ago
Read 2 more answers
What is the range of f(x)?
Sliva [168]
The range of f(x) is [0,∞), which is all non-negative real numbers.
3 0
2 years ago
ANSWER ASAP PLEASE HELP
LiRa [457]

Answer:

I'm guessing 6

Step-by-step explanation:

It's probably wrong.. Sorry :(

8 0
3 years ago
Read 2 more answers
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