Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:21 I used math. way. it is a great app
you do 5-12= -7x-3=21 . in the calculator you don't need the (-s)
Answer:
all: 19,619
monthly: 467.14
Step-by-step explanation:
The answer is $1.6
Step 1. Find the mean of all values (X = ?).
Step 2. Find the distance of all values from the mean (d1, d2, d3, d4, d5).
Step 3. Find the mean of distances (D).
x1 = $12
x2 = $9
x3 = $6
X4 = $8
x5 = $10
Step 1.
X = (x1 + x2 + x3 + x4 + x5)/5
= (12 + 9 + 6 + 8 + 10)/5
= 45/5
= $9
Step 2.
d1 = 12 - 9 = 3
d2 = 9 - 9 = 0
d3 = 9 - 6 = 3
d4 = 9 - 8 = 1
d5 = 10 - 9 = 1
Step 3.
D = (d1 + d2 + d3 + d4 + d5)/5
= (3 + 0 + 3 + 1 + 1)/5
= 8/5
= $1.6
