Evaluate this problem 3/5 - 1/4
2 answers:
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Answer:
See below.
Step-by-step explanation:
RSTV is a quadrilateral. We see that segments RV and RS are congruent. We also see that segments TV and TS are congruent. That makes quadrilateral RSTV a kite. A kite is a quadrilateral that has one set of congruent adjacent sides and a second set of congruent adjacent sides. One set of congruent adjacent sides may or may not be congruent to the second set of congruent adjacent sides. In this case they are not.
The diagonals of a kite are perpendicular which is shown in your figure with segment VS perpendicular to segment RT. The diagonals form 4 right triangles. The 4 right triangles are VRW, SRW, VTW, and STW.
Triangles VRW and SRW are congruent.
Triangles VTW and STW are congruent.
Let's work on the angles first.
Let's work on triangle VTW.
Angle VWT is a right angle.
m<VWT = 90
m<WVT = 42
m<VWT + m<VTW + m<WVT = 180
90 + 42 + m<WVT = 180
m<WVT + 132 = 180
m<WVT = 48
Triangle SWR is a right triangle.
m<RWS + m<RSW + m<SRW = 180
90 + m<RSW + 21 = 180
m<RSW + 111 = 180
m<RSW = 69
Triangles WVR and WSR are congruent with corresponding angles WVR and WSR.
m<WVR = m<WSR = 69
m<TVR = m<WVT + m<WVR
m<TVR = 48 + 69 = 117
m<TVR = 117
Now we deal with sides.
Let's look at triangle VWT.
Side VT is the hypotenuse.
m<VTW = 42 deg
VT = 15
For angle VTW, VW is the opposite leg, and VT is the hypotenuse.
The trig ratio that relates the opposite leg and the hypotenuse is the sine.
VW = 10
Since triangles RVW and RSW are congruent, corresponding sides VW and SW are congruent.
SW = VW = 10
Trianlge RSW is a right triangle with right angle RWS.
For angle WRS, SW is the opposite leg. RW is the adjacent leg.
RW = 26
We now know VW and RW. Using the Pythagorean theorem we can find RV.
(RW)^2 + (VW)^2 = (RV)^2
26^2 + 10^2 = (RV)^2
RV = 28
Perimeter:
Triangles RVT and RST are congruent, so we have:
RV = RS = 28
VT = ST = 15
perimeter = RS + RV + VT + ST
perimeter = 28 + 28 + 15 + 15
perimeter = 86
We are given : The mass of a grain of sand =
Bag contains = 10 kilograms of sand.
Let us concert 10 kg into grams first.
1 kg = 1000 grams.
10 kg = 10 × 1000 = 10000 grams = 10^4.
Therefore, bag contains 10^4 grams of sand.
Therefore, number of grains of sand are in the bag of sand of 10^4 grams =
The mass of a grain of sand in grams ÷ The mass of a grain of sand.
=
=
Therefore, grains of sand are in the bag of 10kg sand.