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Deffense [45]
3 years ago
15

Solve for y when x=-2 -9x-3y=6

Mathematics
1 answer:
Sever21 [200]3 years ago
7 0
-9x - 3y = 6, x = -2

Plug in -2 for x.

-9(-2) - 3y = 6

Simplify.

18 - 3y = 6

Subtract 18 from both sides.

-3y = 6 - 18

Simplify.

-3y = -12

Divide both sides by -3.

y = -12/-3

Simplify.

y = 4

~Hope I helped!~
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Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0
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,

• The solution to the quadratic equation is

x=\frac{1+2i}{5}\text{     or    }\frac{1-2i}{5}

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

,

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}

Note that:

√-1 = i

x=\frac{2\pm\sqrt[]{16\times-1}}{10}

x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}x=\frac{2\pm4i}{10}x=\frac{2}{10}\pm\frac{4i}{10}x=\frac{1}{5}\pm\frac{2}{5}ix=\frac{1\pm2i}{5}

That is;

\text{Either x=}\frac{1+2i}{5}\text{ or     x=}\frac{1-2i}{5}

7 0
1 year ago
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