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3 years ago

14

The scatter plot shows how much puppy weighs within a certain time period. about how much did the puppy gain during this time pe

riod?

1 answer:

GREYUIT [131]3 years ago

6 0

Where is the picture to answer it?

You might be interested in

Solve log(2x+3)=3<br><br> A. 500<br> B. 997<br> C. 1/2<br> D. 997/2

kondor19780726 [428]

2x+3=10^3 now solve for x.....hope it helps

3 0

4 years ago

What is the slope of y=-x perpendicular to the equation

tensa zangetsu [6.8K]

$\frac{1}{2} x$

7 0

3 years ago

Andrea had 32 problems to do for mathematics homework over the weekend. She did 1/4 of the problems on Friday night, and on Satu

igor_vitrenko [27]

Answer:

24

Step-by-step explanation:

Problems at start = 32

-Problems done Friday = ¼ × 32 = <u> 8</u>

Problems still to be done = 24

Andrea had to do 24 problems on Saturday to complete the homework.

6 0

3 years ago

What is the trigonometric ratio for sin Z ?

Schach [20]

In all right triangles, the ratio between a leg and the hypothenuse is the sine of the angle opposite to the leg.

So, in your case, we have

$\sin(Z) = \dfrac{XY}{XZ}$

In order to find XY, we have

$XY = \sqrt{XZ^2-YZ^2} = \sqrt{1600-1024}=\sqrt{576} = 24$

So, the ratio for the sine is

$\sin(Z) = \dfrac{XY}{XZ} = \dfrac{24}{40} = \dfrac{3}{5}$

6 0

3 years ago

A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

5 0

4 years ago