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S_A_V [24]
3 years ago
8

Find the domain of the function

Mathematics
1 answer:
NeX [460]3 years ago
5 0
For Domain<span>, you just need to watch out for Square Roots and/or Fractions! 1) a POLYNOMIAL (no square roots or fractions), i.e. f(x) = x^2 + 3x + 1, </span>domain<span> is "all real numbers." 2) a FRACTION (w/ no square root), i.e. f(x) = (2x+1)/(x^2+5x+6). Set bottom "not equal" to zero.</span>
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PLEASE HELP THIS IS DUE!!!
Rashid [163]

Answer:

432

Step-by-step explanation:

b x h (base x height)

the base is 27 yards and the height is 16.

27 x 16 = 432

5 0
3 years ago
Esibu and Dela are in a part-time business manufacturing clock case. Esibu must work 4 hours and Dela 2 hours to complete one ca
Sav [38]

Answer:

Correct Answer:

<em>To maximize their profit, Esibu must build 6 (2 grandmother clock and 4 wall clock) while Dela must build 8 (6 grandmother clock and 2 wall clock).</em>

Step-by-step explanation:

Since they don't want to work for more than 20 hrs in a week

In-order to maximize the profit,

For Esibu,

2 grandmother clock = 4 hours ×2 = 8 hours

4 wall clock = 3 hours × 4 = 12 hours

Total hours = 20 hours.

For Dela,

6 grandmother clock = 2 hours × 6 = 12 hours

2 wall clock = 4 hours × 2 = 8 hours

Total hours = 20 hours.

6 0
4 years ago
A vending machine operator has determined that the number of candy bars sold per week by a certain machine is a random variable
antiseptic1488 [7]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
A culture started with 5,000 bacteria. After 2 hours, it grew to 5,500 bacteria. Predict how many bacteria will be present after
Luden [163]

Answer:

8,056

Step-by-step explanation:

I took the application

8 0
3 years ago
Given: ΔWXY is isosceles with legs WX and WY; ΔWVZ is isosceles with legs WV and WZ. Prove: ΔWXY ~ ΔWVZ
Alex777 [14]

Answer:

By AA

ΔWXY ~ΔWVZ

Step-by-step explanation:

Here WXY is an isosceles triangle with legs WX & WY

So WX = WY

Hence ∠X = ∠Y

So ∠2= ∠3.

Now by angle sum property

∠1 + ∠2+∠3 = 180°

∠1+∠2+∠2=180°

2∠2 = 180° - ∠1     .......(1)

In triangle WVZ

WV = WZ

So ∠V = ∠Z

∠4 = ∠5

Once again by angle sum property

∠1 + ∠4 + ∠5=180°

∠1 + ∠4 + ∠4 = 180°

2∠4 = 180° - ∠1       ...(2)

From (1) & (2)

2∠2 = 2∠4

∠2=∠4

Now ∠W is common to both triangles

Hence by AA

ΔWXY ~ΔWVZ

8 0
4 years ago
Read 2 more answers
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