Use distance formula d=sqrt root (y2-y1)^2+(x2-x1)^2. So (-3, 4) and (1, 7). D= sqrt root ( 7-4)^2+(-3+1)^2. So now solve d= sqrt (3)^2+(-2)^2. Now d= sqrt 9+4. D= sqrt 13 or 3.60555
MASS*GRAV*HEIGHT=PE
MASS=3
GRAV=9.8
HEIGHT=4.5
3*9.8*4.5=132.3
POTENTIAL ENERGY= 132.3
Hi there!
Since 1 - 5/6 = 1/6, 1/6 of the pizza is left.
Hope this helps!
Answer:
Step-by-step explanation:
I can't see the pic but I would be glad to help you.
Solving the quadratic function, it is found that the particle returns to the ground after 7 seconds.
<h3>What is the quadratic function for the particle's height?</h3>
The particle's height after t seconds is modeled by the following equation:
s(t) = -16t² + v(0)t.
In which v(0) is the initial velocity of the particle, which in this problem is of 112 ft/s, hence:
s(t) = -16t² + 112t.
The particle hits the ground when s(t) = 0, hence:
s(t) = 0
-16t² + 112t = 0
-16t(t - 7) = 0.
Hence the non-trivial solution is:
t - 7 = 0 -> t = 7.
The particle returns to the ground after 7 seconds.
More can be learned about quadratic functions at brainly.com/question/24737967
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