Question

A line is drawn through (-7, 11) and (8, -9). The equation

Answer 1

Answer:

$4x+3y=5$

$y=-\frac{4}{3}x+\frac{5}{3}$

Step-by-step explanation:

we have the points

(-7, 11) and (8, -9)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute

$m=\frac{-9-11}{8+7}$

$m=-\frac{20}{15}$

Simplify

$m=-\frac{4}{3}$

Write the equation in point slope form

$y-y1=m(x-x1)$

we have

$m=-\frac{4}{3}$

$point\ (-7, 11)$

substitute

$y-11=-\frac{4}{3}(x+7)$

Convert to standard form

we have

$y-11=-\frac{4}{3}(x+7)$

Multiply by 3 both sides

$3y-33=-4x-28\\4x+3y=5$

Convert to slope intercept form

we have

$y-11=-\frac{4}{3}(x+7)$

Isolate the variable y

$y=-\frac{4}{3}x-\frac{28}{3}+11$

$y=-\frac{4}{3}x+\frac{5}{3}$